[NCERT]*Mathematics NCERT Class 6th SOLUTION IN ENGLISH : CHAPTER-1 KNOWING OUR NUMBER PDF Free Download

CHAPTER-1 KNOWING OUR NUMBER

MATHEMATICS CLASS-6th NCERT BOOK SOLUTION IN ENGLISH

Mathematics NCERT Books Solution In HIndi PDF Free Download for Class 6th


There are many books in the market but “NCERT Books” stand alone in the market.  Candidates preparing for civil services examinations as well as CBSE aspirants require good books and resources for high level preparation.

Here we are providing the facility to download Latest Edition (2020-21 Academic Year)MATHEMATICS NCERT Books,Solution And Notes HIndi & English totally free for class 6th students. You can download NCERT text-books as well as their solutions & Notes for Hindi & English medium schools.


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-1 KNOWING OUR NUMBER

EXERCISE-1.1

1. Fill in the blanks:


a. 1 lakh -------------------- ten thousand
b. 1 million----------------- hundred thousand
c. 1 crore ------------------- ten lakh
d. 1 crore --------------- million 
e. 1 million ------------- lakh

Answer:

a. ten
b. ten
c. ten 
d. ten
e. ten


2. Place commas correctly and write the numerals:

a. Seventy three lakh seventy five thousand three hundred seven.
b. Nine crore five lakh forty one.
c. Seven crore fifty two lakh twenty one thousand three hundred two.
d. fifty eight million four hundred twenty three thousand two hundred two.
e. Twenty three lakh thirty thousand ten.

Answer:

(a) 73,75,307 
(b) 9,05,00,041
(c) 7,52,21,302 
(d) 58,423,202
(e) 23,30,010



3. Insert commas suitable and write the names according to Indian system of numeration :

(a) 87595762
(b) 8546283
(c) 99900046
(d) 98432701

Answer:

(a) 8,75,95,762 → Eight crore seventy-five lakh ninety-five thousand seven hundred sixty-two
(b) 85,46,283 → Eight-five lakh forty-six thousand two hundred eighty-three
(c) 9,99,00,046 → Nine crore ninety-nine lakh forty-six
(d ) 9,84,32,701 → Nine crore eighty-four lakh thirty-two thousand seven hundred one


4. Insert commas suitable and write the names according to International system of numeration:

(a) 78921092
(b) 7452283
(c) 99985102
(d) 48049831

Answer:

(a) 78,921,092 → Seventy-eight million nine hundred twenty-one thousand ninety-two
(b) 7,452,483 → Seven million four hundred fifty-two thousand two hundred eighty-three
(c) 99,985,102 → Ninety-nine million nine hundred eighty-five thousand one hundred two
(d) 48,049,831 → Forty-eight million forty-nine thousand eight hundred thirty-one


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-1 KNOWING OUR NUMBER

EXERCISE-1.2

1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Answer:

Number of tickets sold on first day = 1,094 
Number of tickets sold on second day = 1,812 
Number of tickets sold on third day = 2,050 
Number of tickets sold on fourth day =  2,751 
Total tickets sold = 1094 + 1812 + 2050 + 2751 = 7,707 
Therefore, 7,707 tickets were sold on all the four days.


2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Answer:

Runs to achieve = 10,000 
Runs scored = 6980
Runs required = 10000 - 6980 =  3,020 
Therefore, he needs 3,020 more runs.  


3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Answer:

Number of votes secured by successful candidates = 5,77,500 
Number of votes secured by his nearest rival = 3,48,700 
Margin between them  = 5,77,500  – 3,48,700  = 2,28,800 
Therefore, the successful candidate won by a margin of 2,28,800 votes. 


4. Kirti Bookstore sold books worth ` 2,85,891 in the first week of June and books worth ` 4,00,768 in the second week o the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Answer:

Books sold in first week = 2,85,891 
Books sold in second week = 4,00,768 
Total books sold =  2,85,891 +  4,00,768  = 6,86,659 
Since, 4,00,768,> 2,85,891 
Therefore sale of second week is greater than that of first week. 
Books sold in second week = 4,00,768 
Books sold in first week =  2,85,891 
More books sold in second week = 4,00,768  – 2,85,891   = 1,14,877 
Therefore, 1,14,877 more books were sold in second week. 


5. Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.

Answer:

Greatest five-digit number using digits 6,2,7,4,3 = 76432 
Smallest five-digit number using digits 6,2,7,4,3 = – 23467 
Difference = 76432 – 23467   = 52965 
Therefore the difference is 52965


6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Answer:

Number of screws manufactured in one day = 2,825 
Number of days in the month of January (31 days) = 2,825 x 31 = 87,575 
Therefore the machine produced 87,575 screws in the month of January. 


7. A merchant had ` 78,592 with her. She placed an order for purchasing 40 radio sets at ` 1,200 each. How much money will remain with her after the purchase?

Answer:

 Cost of one radio =  1200 
Cost of 40 radios = 1200 x 40 =  48,000 
Now, 
Total money with merchant =  78,592 
Money spent by her =   48,000 
Money left with her = 78,592 - 48,000  =  30,592 
Therefore, ` 30,592 will remain with her after the purchase.


8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?

Answer:

Wrong answer = 7236 x 65 = 470340
Correct answer = 7236 x 56 = 405216
Difference in answers = 470340 – 405216 = 65,124



9. To stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?

Answer:

Cloth required to stitch one shirt = 2 m 15 cm
 = 2 x 100 cm + 15 cm
 = 215 cm 
Length of cloth = 40 m = 40 x 100 cm = 4000 cm 
Number of shirts can be stitched = 4000 ÷ 215 
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.


10. Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?

Answer:

The weight of one box = 4 kg 500 g 
= 4 x 1000 g + 500 g = 4500 g 
Maximum load can be loaded in van = 800 kg 
= 800 x 1000 g = 800000 g 
Number of boxes = 800000 ÷ 4500
Therefore, 177 boxes can be loaded. 


11. The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.

Answer:

Distance between school and home = 1.875 km 
Distance between home and school =  1.875 km 
Total distance covered in one day = 1.875 km + 1.875 km  = 3.750 km 
Distance covered in six days = 3.750 x 6 = 22.500 km 
Therefore, 22 km 500 m distance covered in six days.


12. A vessel has 4 liters and 500 ml of curd. In how many glasses each of 25 ml capacity, can it be filled?

Answer:

Capacity of curd in a vessel = 4 liters 500 ml
 = 4 x 1000 ml + 500 ml = 4500 ml 
Capacity of one glass = 25 ml 
Number of glasses can be filled = 4500 ÷ 25 = 180
Therefore, 180 glasses can be filled by curd.


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-1 KNOWING OUR NUMBER

EXERCISE-1.3

1. Estimate each of the following using general rule: 

(a) 730 + 998 

ANSWER:

730 round off to  = 700 

998 round off to = 1000

estimated sum = 1000 + 700 = 1700


(b) 796 – 314

 ANSWER:

796 round off to = 800

314 round off to = 300

estimated difference = 800 - 300 = 500


(c) 12,904 + 2,888 

ANSWER:

12904 round off to 13000

998 round off to 3000

estimated sum = 13000 + 3000 = 16000


(d) 28,292 – 21,496

ANSWER:

28292 round off to 28000

21496 round off to 21000

estimated difference = 28000 - 21000 = 7000


2. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens): 

(a) 439 + 334 + 4317 

ANSWER:

439 round off to 400

334 round off to 300

4317 round off to 4300

estimated sum = 400 + 300 + 4300 = 5000


(b) 1,08,737 – 47,599 

ANSWER:

108737 round off to 108700

47599 round off to 47600

estimated difference = 108700 - 47600 = 61100


(c) 8325 – 491 

ANSWER:

8325 round off to 8300

491 round off to 500

estimated difference = 8300 - 500 = 7800


(d) 4,89,348 – 48,365

ANSWER:

489348 round off to 489300

48365 round off to 48400

 estimated difference = 489300 - 48400 = 440900


3. Estimate the following products using general rule: 

(a) 578 x 161 

ANSWER:

578 round off to 600 

161 round off to 200 

The estimated product = 600 x 200 = 1,20,000


(b) 5281 x 3491 

ANSWER:

5281 round of to 5,000 

3491 round off to 3,500 

The estimated product = 5,000 x 3,500 = 1,75,00,000 


(c) 1291 x 592 

ANSWER:

1291 round off to 1300 

592 round off to 600 

The estimated product = 1300 x 600 = 7,80,000


(d) 9250 x 29

ANSWER:

9250 round off to 10,000 

229 round off to 30 

The estimated product = 10,000 x 30 = 3,00,000


👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈


Here we are providing the facility to download Latest Edition (2020-21 Academic Year)MATHEMATICS NCERT Books,Solution And Notes HIndi & English totally free for class 6th students. You can download NCERT text-books as well as their solutions & Notes for Hindi & English medium schools.


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

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