[NCERT]*Mathematics NCERT Class 6th SOLUTION IN ENGLISH : CHAPTER-2 WHOLE NUMBER PDF Free Download

 

CHAPTER-2 WHOLE NUMBER

MATHEMATICS CLASS-6th NCERT BOOK SOLUTION IN ENGLISH

Mathematics NCERT Books Solution In HIndi PDF Free Download for Class 6th


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Here we are providing the facility to download Latest Edition (2020-21 Academic Year)MATHEMATICS NCERT Books,Solution And Notes HIndi & English totally free for class 6th students. You can download NCERT text-books as well as their solutions & Notes for Hindi & English medium schools.


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

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MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-2 WHOLE NUMBER

EXERCISE-2.1

1. Write the next three natural numbers after 10999.

ANSWER:

10,999 + 1 = 11,000 

11,000 + 1 = 11,001 

11,001 + 1 = 11,002 

 

2. Write the three whole numbers occurring just before 10001

ANSWER:

10,001 – 1 = 10,000 

10,000 – 1 = 9,999 

9,999 – 1 = 9,998


3. Which is the smallest whole number?

ANSWER:

 ‘0’ (zero) is the smallest whole number.


4. How many whole numbers are there between 32 and 53? 

ANSWER:

53 – 32 – 1 = 20 

There are 20 whole numbers between 32 and 53.


5. Write the successor of: 

(a) 2440701 

ANSWER:

Successor of 2440701 is 2440701 + 1 = 2440702


(b) 100199 

ANSWER:

Successor of 100199 is 100199 + 1 = 100200

 

(c) 1099999 

ANSWER:

Successor of 1099999 is 1099999 + 1 = 1100000


(d) 2345670

ANSWER:

Successor of 2345670 is 2345670 + 1 = 2345671


6. Write the predecessor of: 

(a) 94 

ANSWER:

The predecessor of 94 is 94 – 1 = 93


(b) 10000 

ANSWER:

The predecessor of 10000 is 10000 – 1 = 9999

(c) 208090 

ANSWER:

The predecessor of 208090 is 208090 – 1 = 208089

(d) 7654321 

ANSWER:

The predecessor of 7654321 is 7654321 – 1 = 7654320


7. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them. 

(a) 530, 503 

ANSWER:) 530 > 503; 

So 503 appear on left side of 530 on number line.


(b) 370, 307 

ANSWER:) 370 > 307; 

So 307 appear on left side of 370 on number line.


(c) 98765, 56789 

ANSWER:) 98765 > 56789; 

So 56789 appear on left side of 98765 on number line.


(d) 9830415, 10023001

ANSWER:) 9830415 < 10023001; 

So 9830415 appear on left side of 10023001 on number line.


8. Which of the following statements are true (T) and which are false (F): 

(a) Zero is the smallest natural number. 

ANSWER:) False

(b) 400 is the predecessor of 399. 

ANSWER:) False

(c) Zero is the smallest whole number. 

ANSWER:) True

(d) 600 is the successor of 599. 

ANSWER:) True

(e) All natural numbers are whole numbers. 

ANSWER:) True

(f) All whole numbers are natural numbers. 

ANSWER:) False

(g) The predecessor of a two digit number is never a single digit number. 

ANSWER:) False 

(h) 1 is the smallest whole number. 

ANSWER:) False

(i) The natural number 1 has no predecessor. 

ANSWER:) True 

(j) The whole number 1 has no predecessor. 

ANSWER:) False 

(k) The whole number 13 lies between 11 and 12.

ANSWER:) False 

(l) The whole number 0 has no predecessor. 

ANSWER:) True

(m) The successor of a two digit number is always a two digit number.

ANSWER:) False


[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-2 WHOLE NUMBER

EXERCISE-2.2

1. Find the sum by suitable rearrangement: 

(a) 837 + 208 + 363 

Ans: 837 + 208 + 363

= (837 + 363) + 208

= 1200 + 208 

= 1408

 

(b) 1962 + 453 + 1538 + 647

Ans: 1962 + 453 + 1538 + 647

= (1962 + 1538) + (453 + 647)

= 3500 + 1100

= 4600


2. Find the product by suitable arrangement: 

(a) 2 x 1768 x 50 

Ans:2 x 1768 x 50

= (2 x 50) x 1768

= (2 x 50) x 1768

= 176800

 

(b) 4 x 166 x 25 

Ans: 4 x 166 x 25

= (4 x 25) x 166

= 100 x 166

= 16600


(c) 8 x 291 x 125 

Ans:) 8 x 291 x 125

= (8 x 125) x 291

= 1000 x 291

= 291000


(d) 625 x 279 x 16 

Ans:) 625 x 279 x 16

= (625 x 16) x 279

= 10000 x 279

= 2790000


(e) 285 x 5 x 60 

Ans:) 285 x 5 x 60

= 284 x (5 x 60)

= 284 x 300

= 85500


(f) 125 x 40 x 8 x 25

Ans:)125 x 40 x 8 x 25

= (125 x 8) x (40 x 25)

= 1000 x 1000 

= 1000000


 3. Find the value of the following: 

(a) 297 x 17 + 297 x 3 

Ans:) 297 x 17 + 297 x 3

= 297 x (17 + 3)

= 297 x 20

= 5940


(b) 54279 x 92 + 8 x 54279 

Ans:)54279 x 92 + 8 x 542379

= 54279 x (92 + 8)

= 54279 x 100

= 5427900


(c) 81265 x 169 – 81265 x 69 

Ans:)81265 x 169 – 81265 x 69

= 81265 x (169 – 69)

= 81265 x 100

= 8126500


(d) 3845 x 5 x 782 + 769 x 25 x 218

Ans:)3845 x 5 x 782 + 769 x 25 x 218

= 3845 x 5 x 782 + 769 x 5 x 5 x 218)

= 3845 x 5 x 782 + 3845 x 5 x 218

= 3845 x 5 x (782 + 218)

= 3845 x 5 x 1000

= 19225000


4. Find the product using suitable properties: 

(a) 738 x 103 

Ans:)) 738 x 103

= 738 x (100 + 3) 

= 738 x 100 + 738 x 3 

= 73800 + 2214

= 76014

 

(b) 854 x 102 

Ans:) 854 x 102

= 854 x (100 + 2)

= 854 x 100 + 854 x 2

= 85400 + 1708

= 87108


(c) 258 x 1008 

Ans:) 258 x 1008

= 258 x (1000 + 8)

= 258 x 1000 + 258 x 8

= 258000 + 2064

= 260064


(d) 1005 x 168

Ans:)1005 x 168

= (1000 + 5) x 168

= 1000 x 168 + 5 x 168

= 168000 + 840

= 168840


5. A taxi-driver, filled his car petrol tank with 40 liters of petrol on Monday. The next day, he filled the tank with 50 liters of petrol. If the petrol costs ` 44 per liter, how much did he spend in all on petrol?

Ans:) 

Petrol filled on Monday = 40 liters 
Petrol filled on next day = 50 liters 
Total petrol filled = 90 liters 
Now, Cost of 1 liter petrol = ` 44 
Cost of 90 liters petrol = 44 x 90 
= 44 x (100 – 10) 
= 44 x 100 – 44 x 10
= 4400 – 440 = ` 3960 
Therefore, he spent ` 3960 on petrol.


6. A vendor supplies 32 liters of milk to a hotel in a morning and 68 liters of milk in the evening. If the milk costs ` 15 per liter, how much money is due to the vendor per day?
Ans:) 
Supply of milk in morning = 32 liters 
Supply of milk in evening = 68 liters 
Total supply = 32 + 68 = 100 liters 
Now, Cost of 1 liter milk = ` 15 
Cost of 100 liters milk = 15 x 100 = ` 1500 
Therefore, ` 1500 is due to the vendor per day.


7. Match the following: 
(i) 425 x 136 = 425 x (6 + 30 + 100)    (a) Commutativity under multiplication 
(ii) 2 x 48 x 50 = 2 x 50 x 49                (b) Commutativity under addition 
(iii) 80 + 2005 + 20 = 80 + 20 + 2005  (c) Distributivity multiplication under addition

Ans:) 

(i) 425 x 136 = 425 x (6 + 30 + 100)   (c) Distributivity of multiplication over addition 
(ii) 2 x 49 x 50 = 2 x 50 x 49               (a) Commutivity under multiplication 
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (b) Commutivity under addition





[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

MATHEMATICS NCERT CLASS 6th BOOK SOLUTION (CHAPTER WISE) ENGLISH

👉नोट:- लिंक पर क्लिक करें और पढ़े। 👈

👉THE ULTIMATE LEARNER👈

CHAPTER-2 WHOLE NUMBER

EXERCISE-2.3

1. Which of the following will not represent zero: 

(a) 1 + 0 

(b) 0 x 0 

(c) 0/2 

(d) 10-10/2

Ans:) 

(a) [1 + 0 is equal to 1]


 2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Ans:)

Yes, if we multiply any number with zero the resultant product will be zero. 

Example: 2 x 0 = 0, 5 x 0 = 0, 9 x 0 = 0 

If both numbers are zero, then the result also be zero. 0 x 0 = 0


3. If the product of two whole number is 1, can we say that one or both of them will be 1? Justify through examples.

Ans:)

If only one number be 1 then the product cannot be 1. 

Examples: 5 x 1 = 5, 4 x 1 = 4, 8 x 1 = 8 

If both number are 1, then the product is 1 

1 x 1 = 1 


4. Find using distributive property: 

(a) 728 x 101 

Ans:)728 x 101

= 728 x (100 + 1)

= 728 x 100 + 728 x 1

= 72800 + 728

= 73528 

(b) 5437 x 1001 

Ans:)5437 x 1001

= 5437 x (1000 + 1)

= 5437 x 1000 + 5437 x 1

= 5437000 + 5437

= 5442437


(c) 824 x 25 

Ans:) 824 x 25

= 824 x (20 + 5)

= 824 x 20 + 824 x 5

= 16480 + 4120

= 20600


(d) 4275 x 125 

Ans:)4275 x 125

= 4275 x (100 + 20 + 5)

= 4275 x 100 + 4275 x 20 + 4275 x 5

= 427500 + 85500 + 21375

= 534375


(e) 504 x 35

Ans:)504 x 35 

= (500 + 4) x 35 

= 500 x 35 + 4 x 35

= 17500 + 140

= 17640


5. Study the pattern: 

1 x 8 + 1 = 9; 

12 x 8 + 2 = 98; 

123 x 8 + 3 = 987:

1234 x 8 + 4 = 9876; 

12345 x 8 + 5 = 98765:

Write the next two steps. Can you say how the pattern works?

Ans:)

123456 x 8 + 6 = 987654 

1234567 x 8 + 7 = 9876543 

Pattern works like this: 

 1 x 8 + 1 = 9 

 12 x 8 + 2 = 98 

 123 x 8 + 3 = 987 

 1234 x 8 + 4 = 9876 

 12345 x 8 + 5 = 98765

 123456 x 8 + 6 = 987654

 1234567 x 8 + 7 = 9875643






[NCERT]*Mathematics NCERT Class 6th Books , Solution , Notes HIndi & English PDF Free Download

[NCERT]*Mathematics NCERT Class 6th Books IN English PDF Free Download

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